Question

eva draws a line that includes the points (2,0) and (-2,2). Which function gives all the points (x,y) on this line.

Answer 1

Answer:

Step-by-step explanation:

Answer 2

$y = \dfrac{2-x}{2}$

is the require function.

Step-by-step explanation:

We are given the following in the question:

A line passes through the points

(2,0) and (-2,2)

An equation of line passing through theses points will give the function satisfied by (x,y) on this line.

Equation of line:

$(y-y_1) = \displaystyle\frac{y_2-y_2}{x_2-x_1}(x-x_1)$

where, $(x_1,y_1), (x_2.y_2)$ is the point through which the line passes.

The equation of line is:

$(y-0) = \displaystyle\frac{2 - 0}{-2-2}(x-2)\\\\y= \frac{1}{-2}(x-2)\\\\-2y = x-2\\x + 2y - 2=0\\\\y = \dfrac{2-x}{2}$

is the require function.

#LearnMore

A line is passing through the points (2,2) and is perpendicular to the line 3x+y=3 find its equation

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