Math, asked by mokshkaushish, 1 year ago

evaculate( 2a-3b)(2a+3b)+(3b-c)(3b+c)+(c-2a)(c+2a]​

Answers

Answered by 001100
9

Answer:

( 2a-3b)(2a+3b)+(3b-c)(3b+c)+(c-2a)(c+2a]

=(2a)^2-(3b)^2+(3b)^2-(c)^2+(c)^2-(2a)^2

=4a^2-9b^2+9b^2-c^2+c^2-4a^2

=0

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