Math, asked by rishabsinghsrinet459, 22 days ago

evalu evaluate 3 cos 55 degree upon 7 sin 35 degree + under root 3 bracket 10 10 theta 10:30 1040 to 1050 1060 1080 close

Answers

Answered by as7803617
1

Answer:

We know,

cos(90−θ)=sinθ

tan(90−θ)=cotθ

cotθ=

tanθ

1

secθ=

cosθ

1

cos55

=cos(90

−35

)=sin35

tan5

=tan(90

−85

)=cot85

tan25

=tan(90

−65

)=cot65

csc20

=sec(90

−70

)=sec70

To evaluate,

7sin35

3cos55

7(tan5

tan25

tan45

tan65

tan85

)

4(cos70

csc20

)

=

7sin35

3sin35

7(tan5

tan25

tan45

cot25

cot5

)

4(cos70

sec70

)

=

7

3

7(tan45

tan25

tan5

cos70

)

4(cos70

tan5

tan25

)

=

7

3

7

4

=

7

−1

Answered by sunitanishan4923
0

Answer:

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