Evaluat each of the following using identities
(y+3) ³
Answers
Answered by
1
Answer:
using identity =(a+b)^3=a3+b3+3ab(a+b)
(y+3)3=y3+3^3+3×y×3(y+3)
y3+27+9y(y+3)
y3+27+9y2+27y
Answered by
3
Answer:
by using identity
(a+b)^3= a^3+b^3 +3ab^2 - 3a^2b
(y+3)^3 = y^3 +( 3)^3 + 3 × y×(3)^2 + 3×(y)^2 ×3
= y^3 + 27 + 27y - 9y^2
the answer is
y^3 - 9y^2 + 27y + 27
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