evaluat the following:1+i+i²+i³+.........+i⁹⁹/1+i+i²+i³+.........+i³³
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Answer:
=−1
{i}^{4} = {i}^{2} \times {i}^{2} = 1i
4
=i
2
×i
2
=1
{i}^{364} = {( {i}^{4} )}^{91} = {1}^{91} = 1i
364
=(i
4
)
91
=1
91
=1
Also,
{i}^{368} = {i}^{364} \times {i}^{4} = 1 \times 1 = 1i
368
=i
364
×i
4
=1×1=1
Similarly
{i}^{370} = {i}^{368} \times {i}^{2} = 1 \times - 1 = - 1i
370
=i
368
×i
2
=1×−1=−1
{i}^{372} = {i}^{368} \times {i}^{4} = 1 \times 1 = 1i
372
=i
368
×i
4
=1×1=1
{i}^{374} = - 1i
374
=−1
{i}^{378} = - 1i
378
=−1
{i}^{380} = 1i
380
=1
{i}^{382} = - 1i
382
=−1
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