Math, asked by nehuchavan2019, 4 days ago

evaluat the following. c. (1001) ³​

Answers

Answered by dharmvirsingh79
0

Answer:

(a+b)^3=a^3+b^3+3ab(a+b) FORMuLa

Step-by-step explanation:

(1000+3)^3=1000^3+3^3+3(1000)(3)(1000+3)

= 1000000000+27+9000(1000+3)

= 1000009027003

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Answered by βαbγGυrl
1

Answer:

\sf{ (1000+1)^3}

Now using the identity (a+b)3  =a3  +b3  +3ab(a+b), we get

(100+3)^3 =100^3

+3^3+[(3×100×3)(100+3)]

=1000000+27+(900×103)

=1000000+27+92700

=1092727

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