Question

Evaluate (1.05)² using identities​

Answer 1

Step-by-step explanation:

the power of (1.05)^2 is 1.1025

Answer 2

Question:

Evaluate (1.05)² using identity.

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Solution:

1.05 can also be written as (1+0.05). So, we can write (1.05)² as (1+0.05)²

Now, we have to evaluate,

(1+0.05)²

$\bigstar {\mathcal {\red {Using\ the\ identity\ (a+b)^{2} = a^{2} + 2ab + b^{2}}}}$

= (1)² + 2×1×0.05 + (0.05)²

= 1 + 0.1 + 0.0025

= 1.1025

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Answer:

Value of (1.05)² is 1.1025.

$\:$

More identities:

• (a+b)² = a² + 2ab + b²
• (a-b)² = a² - 2ab + b²
• a² - b² = (a+b) (a-b)
• (x+a) (x+b) = x² + (a+b)x + ab