evaluate (1). (1002)^2 (2). (999)^3
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Hey friend,
Here is the answer you were looking for:
Using the identity
(a + b)^2 = (a)^2 + (b)^2 + 2ab
= (1000)^2 + (2)^2 + 2 × 1000 × 2
= 1000000 + 4 + 4000
= 1004004
2)
(999)^3
= (1000 - 1)^3
Using the identity
(a - b)^3 = (a)^3 - (b)^3 - 3ab (a - b)
= (1000)^3 -(1)^3 - 3 × 1000 × 1 ( 1000 - 1)
= 1000000 - 1 - 3000(999)
= 999999 -2997000
= - 1997001
Hope this helps!!!
@Mahak24
Thanks...
☺☺
Here is the answer you were looking for:
Using the identity
(a + b)^2 = (a)^2 + (b)^2 + 2ab
= (1000)^2 + (2)^2 + 2 × 1000 × 2
= 1000000 + 4 + 4000
= 1004004
2)
(999)^3
= (1000 - 1)^3
Using the identity
(a - b)^3 = (a)^3 - (b)^3 - 3ab (a - b)
= (1000)^3 -(1)^3 - 3 × 1000 × 1 ( 1000 - 1)
= 1000000 - 1 - 3000(999)
= 999999 -2997000
= - 1997001
Hope this helps!!!
@Mahak24
Thanks...
☺☺
Malavika123:
thank u..!
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