Question

evaluate:1/√2+1 +1/√3+√2 +1/√4+√3 +1/√5+√4 +1/√6+√5 +1/√7+√6 +1/√8+√7 +1/√9+√8
​it's very urgent. please send it very fast if anybody can.

Answer 1

Answer:

2

Step-by-step explanation:

1/(√2+√1)+ 1/(√3+√2).........1/(√9+√8)

=

1(√2--√1)/√2+√1(√2-√1)

+1(√3-√2)/√3+√2(√3-√2)

.

.

.

1(√9-√8)/√9+√8(√9-√8)

= √2-√1/√2^2-√1^2

+√3-√2/√3^2-√2^2

.

.

.

√9-√8/√9^2-√8^2

=√2-√1+√3-√2+√4-√3.......+√9-√8/1

== -√1 -+√9

= -1+3

=2