Question

Evaluate [1^-2 + 2^-2 + 3^-2] X 6^2
[Mention the laws used]

Answer 1

Answer:

49

Step-by-step explanation:

exponents and powers

Answer 2

Answer:

7² or 49

Step-by-step explanation:

$({1}^{ - 2} + {2}^{ - 2} + {3}^{ - 2} ) \times {6}^{2} \\ = \frac{1}{ {1}^{2} } + \frac{1}{ {2}^{2} } + \frac{1}{ {3}^{2} } \times {6}^{2} \\ ( {x}^{ - y} = \frac{1}{{x}^{y} } ) \\ \frac{1}{1} + \frac{1}{4} + \frac{1}{9} \times {6}^{2} \\ = \frac{36 + 9 + 4}{36} \times 36 \\ = \frac{49}{36} \times 36 \\ = 49 = {7}^{2}$