Question

evaluate [(1/2)^-3 + (1/3)^-3 + (1/4)^-3 ] / 27

Answer 1

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Here is your answer.

$\frac{(( \frac{1}{2}) {}^{ - 3} + ( \frac{1}{3} ) {}^{ - 3} + ( \frac{1}{4} ) {}^{ - 3} ) }{27} \\ \\ = \frac{( {2}^{3} + {3}^{3} + {4}^{3} ) }{27} \\ \\ = \frac{(8 + 27 + 64)}{27} \\ \\ = \frac{99}{27} \\ \\ = \frac{11}{3}$

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Answer 2

Here is your answer

$= \frac{ {2}^{3} + {3}^{3} + {4}^{3} }{27} \\ = \frac{8 + 27 + 64}{27} \\ = \frac{99}{27}$
Hope it helps