evaluate 1+2-3+4+5-6+.......+2005+2006-2007+2008+2009
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Answered by
2
Answer:
2019045
Step-by-step explanation:
By using a.p. 's summation formula, Sn=n/2*(a+an), where n= 2009, a=1 and an=2009
Sn= 2009/2*(1+2009)
=2009/2*2010
=2009*1005
Sn=2019045
Answered by
1
Answer:
Find the smallest number which when divided by 1088, 640 and 100 leaves 3 as remainder in each case in
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