Evaluate: {{1/2y='+{1/3)*1
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Answered by
3
Correct option is
A
I=
3
2
(1+y
2
)
3/2
+C
Let I=∫
1+y
2
⋅2ydy
Let u=1+y
2
, then du=2y dy.
I=∫u
1/2
du
=
(1/2)+1
u
1/2
+1
[Integrate, using rule no. 3 with n=1/2]
=
3
2
u
3/2
+C [Simpler form]
=
3
2
(1+y
2
)
3/2
+C [Replace u by 1+y
2
].
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