Question

evaluate (1/3)^-1-(1/4)^-1)-1

Answer 1

$Value \: of \: \Big(\frac{1}{3}\Big)^{-1} - \Big(\big(\frac{1}{4}\big)^{-1}\Big)^{-1}$

$= 3^{1} - \Big( \frac{1}{4}\Big)^{(-1) \times (-1)}$

$\underline {\blue { By \: exponential \:Laws :}}$

$\pink { 1) a^{-n} = a^{n} } \\\orange { 2) (a^{m})^{n} = a^{m\times n }}$

$= 3 - \frac{1}{4} \\= \frac{12-1}{4} \\= \frac{11}{4}$

Therefore.,

$\red { Value \: of \: \Big(\frac{1}{3}\Big)^{-1} - \Big(\big(\frac{1}{4}\big)^{-1}\Big)^{-1}}\green {= \frac{11}{4}}$

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Answer 2

Step-by-step explanation:

{(1/3)^-1 - (1/4)^-1}^-1

= {(3)^1 - (4)^1}^-1

= (3 - 4)^-1

= (-1)^-1

= (-1)

HOPE IT HELPS!!!!!!!