evaluate ((1/3)2-1-(1/4)-1)-1 brain my
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Answered by
1
Answer:
(1–1/2)=1/2
(1–1/2)(1–1/3)=1/2×2/3=1/3
(1–1/2)(1–1/3)(1–1/4)=1/2×2/3×3/4=1/3×3/4=1/4
(1–1/2)(1–1/3)(1–1/4)(1–1/5)=1/2×2/3×3/4×4/5=1/4×4/5=1/5
As you can see, the denominator of each term cancels out the numerator of the next term, so this series can be generalised to:
(1–1/2)(1–1/3)(1–1/4)…(1–1/n)=1/n
Which can also be written as:
1/2×2/3×3/4×…×((n-1)/n)=1/n
Which we could even be further generalised to:
a/b×b/c×c/d×…×m/n = a/n
Answered by
2
Answer:
-(31/12)
Step-by-step explanation:
(2/3-1-1/4-1)-1
={(8-12-3-12)/12}-1
=-(19/12)-1
=(-19-12)/12
=-(31/12)
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