Question

Evaluate
(1^3+2^3+3^3)^1/2

Answer 1

Answer:

(1³+ 2³+ 3³)½

= (1 + 8 + 27 )½

= (36)½

= (6²)½

= 6²×½

= 6

Answer 2

Given : ${( {1}^{3} + {2}^{3} + {3}^{3} ) }^{ \frac{1}{2} }$

To find : The evaluation of the given mathematical term.

Solution :

We can simply solve this mathematical problem by using the following mathematical process. (our goal is to evaluate the given mathematical term)

Here, we will be using general laws of indices.

So,

$= {( {1}^{3} + {2}^{3} + {3}^{3} ) }^{ \frac{1}{2} }$

$= {[(1 \times 1 \times 1) + (2 \times 2 \times 2) + (3 \times 3 \times 3)]}^{ \frac{1}{2} }$

$= {(1 + 8 + 27)}^{ \frac{1}{2} }$

$= {(36)}^{ \frac{1}{2} }$

$={ ( {6}^{2} ) }^{ \frac{1}{2} }$

$= {(6)}^{2 \times \frac{1}{2} }$

$= {6}^{1}$

$= 6$

(This will be considered as the final result.)

Hence, the answer will be 6