Math, asked by naomihayanow, 10 months ago

evaluate (1^3+2^3+3^3)^-3/2

Answers

Answered by umangsingh90
3

Answer:

(1^3+2^3+3^3)^‐3/2

=(1+8+27)^‐3/2

=(36)^‐3/2

=((2×3)^2)‐3/2

=(2×3)^‐3

=6^‐3

=1/216

Similar questions