Math, asked by parvathy14, 10 months ago

evaluate 1/√3 sec 60 + cosec 60​

Answers

Answered by Dipanshu4968
12

Value of sec 60 is 2 and cosec 60 is 2/√3

Now,

1/√3*2+2/√3 =2/√3 +2/√3

After solving we get 4√3/3 Ans

Answered by pinquancaro
12

\frac{1}{\sqrt3} \sec 60+\csc 60=0

Step-by-step explanation:

Given : Expression \frac{1}{\sqrt3} \sec 60+\csc 60

To find : Evaluate the expression ?

Solution :

Expression \frac{1}{\sqrt3} \sec 60+\csc 60

Using trigonometric values,

\sec 60^\circ=2

and \csc 60^\circ =\frac{2}{\sqrt 3}

Substitute the value,

\frac{1}{\sqrt3} \sec 60+\csc 60=\frac{1}{\sqrt3}\times 2-\frac{2}{\sqrt3}

\frac{1}{\sqrt3} \sec 60+\csc 60=\frac{2}{\sqrt3}-\frac{2}{\sqrt3}

\frac{1}{\sqrt3} \sec 60+\csc 60=0

#Learn more

Cos30_sin45+cosec 60​

https://brainly.in/question/14187846

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