evaluate 1/3 tan^2 30- 1/3 cos^2 60 + 1/2 sec^2 45 _2/3 sin^2 60
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1/3 tan²30-1/3 cos²60+1/2 sec²45-2/3 sin²60
tan30=1/√3 cos60=1/2 sec45=√2 sin60=√3/2
1/3·(1/√3)²-1/3·(1/2)²+1/2·(√2)²-2/3·(√3/2)²
1/3·1/3-1/3·1/4+1/2·2-2/3·3/4
1/9-1/12+1-1/2
taking LCM
(4-3+36-18)/36
1+18/36
19/36
hope this helps,if u like it please mark it as brainliest
1/3 tan²30-1/3 cos²60+1/2 sec²45-2/3 sin²60
tan30=1/√3 cos60=1/2 sec45=√2 sin60=√3/2
1/3·(1/√3)²-1/3·(1/2)²+1/2·(√2)²-2/3·(√3/2)²
1/3·1/3-1/3·1/4+1/2·2-2/3·3/4
1/9-1/12+1-1/2
taking LCM
(4-3+36-18)/36
1+18/36
19/36
hope this helps,if u like it please mark it as brainliest
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