Question

EVALUATE:

(1/4)^-² - 3 (8)^⅔ × 4⁰ + [9/18]-½​

Answer 1

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$\sf \: ( { \frac{1}{4} })^{ - 2} - 3 {(8)}^{ \frac{2}{3} } {(4)}^{0} + ( { \frac{9}{16} })^{ \frac{ - 2}{1} } = \frac{16}{3}$

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$\sf \: given \: = \\ \sf\: expression \: ( { \frac{1}{4}) }^{ - 2} - 3 {(8)}^{ \frac{2}{3} } {(4)}^{0} + \\ \sf \: {( \frac{9}{16} )}^{ \frac{ - 1}{2} }$

$\sf \: to \: find \: = \: simplyfy \: the \: expression$

$\sf \: expression \: = > \\ \: { (\frac{1}{4} )}^{ - 2} - 3 {(8)}^{ \frac{2}{3} } {(4)}^{0} + {( \frac{9}{16}) }^{ \frac{ - 1}{2} }$

$\sf \: Factor \: the \: bracket \: terms \: into \: power,$

$\sf \: {4}^{2} - 3 ({2}^{3})^{ \frac{2}{3} } \times 1 + { (\frac{3}{4}) }^{2 \times ( \frac{ - 1}{2} )}$

$= > \: 16 - 3 \times {2}^{2} + {( \frac{3}{4} )}^{ - 1}$

$= > \sf \: 16 - 12 + \frac{4}{3}$

$\sf \: = > \: 4 + \frac{4}{3}$

$\sf \: = > \: \frac{12 + 4}{3}$

$\sf \: = > \frac{16}{3} \: is \: your \: answer$

hope it was helpful to you

Answer 2

$\: \: •\huge\bigstar{\underline{{\red{A}{\pink{n}{\color{blue}{s}{\color{gold}{w}{\color{aqua}{e}{\color{lime}{r}}}}}}}}}\huge\bigstar•$

hope it was helpful to you