Evaluate 1/alpha^2 - 1/beta^2
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Answered by
1
Answer:
Answer:
ax² + bx +c =0
zeroes α,β
sum of roots = α+β = -b/a
products of roots = αβ = c/a
1/α - 1/β = β-α / αβ ............(1)
β-a = √(b² - 4ac/a² ) putting this value
1/α - 1/β = √(b²-4ac/a²) / c/a = √b²-4ac / c
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Answered by
1
Answer:
b^2/c^2
Step-by-step explanation:
1/alpha^2-1/beta^2
alpha^2+beta^2/(alpha.beta)^2
(-b/a)^2/(c/a)^2
b^2/a^2*c^2/a^2
=b^2/c^2
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