Evaluate:
1+i^2+i^4+i^6+...+i^2n
Answers
Answered by
8
We know that
i^2 => -1
i^4 => 1
i^6 => -1
i^8 => 1
Then
1 -1 +1 -1 + 1-1............(2n+1)
So the odd number term is
-1
i^2 => -1
i^4 => 1
i^6 => -1
i^8 => 1
Then
1 -1 +1 -1 + 1-1............(2n+1)
So the odd number term is
-1
Answered by
6
Answer:
Step-by-step explanation:
We know that
i^2 => -1
i^4 => 1
i^6 => -1
i^8 => 1
Then
1 -1 +1 -1 + 1-1............(2n+1)
So the odd number term is
-1
Similar questions