Math, asked by Sambhavi10, 1 year ago

Evaluate:

1+i^2+i^4+i^6+...+i^2n

Answers

Answered by atul103
8
We know that

i^2 => -1

i^4 => 1

i^6 => -1

i^8 => 1


Then

1 -1 +1 -1 + 1-1............(2n+1)


So the odd number term is

-1
Answered by cv099358
6

Answer:

Step-by-step explanation:

We know that

i^2 => -1

i^4 => 1

i^6 => -1

i^8 => 1

Then

1 -1 +1 -1 + 1-1............(2n+1)

So the odd number term is

-1

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