evaluate (1-i+i²)^-15
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Answered by
0
Answer:
6.96917193762E-8
Step-by-step explanation:
(1-i+i^2)^-15
where i= -1
then (1+1+1)^(-15)
=(3)^(-15) we know that [a^-n = 1/a^n]
=1/(3^15)
=6.96917193762E-8
Answered by
0
Answer:
-i
Step-by-step explanation:
[1-i+i^2 ]^-15 = [1-i-1]^-15 ................................i^2=-1
= [-i]^15
= [i]^14*- i ..................................saprating i
= [i^2]^14*-i
= 1*-i .............................. i2=1 and ans of any positive
power number is positive
=-i
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