Math, asked by swatiholam1980, 7 months ago

evaluate (1-i+i²)^-15​

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Answers

Answered by tejar619
0

Answer:

6.96917193762E-8

Step-by-step explanation:

(1-i+i^2)^-15

where i= -1

then (1+1+1)^(-15)

=(3)^(-15) we know that [a^-n = 1/a^n]

=1/(3^15)

=6.96917193762E-8

Answered by awadhutghavade
0

Answer:

-i

Step-by-step explanation:

[1-i+i^2 ]^-15 = [1-i-1]^-15 ................................i^2=-1

                     = [-i]^15

                     = [i]^14*- i ..................................saprating i

                     = [i^2]^14*-i

                     = 1*-i .............................. i2=1 and ans of any positive

                                                                power number is positive

                      =-i

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