evaluate 1, sin18⁰,cos72⁰
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sin θ - 4 (1 - sin^2 A) + 3 = 0. ⇒ 4 sin^2 A + 2 sin A - 1 = 0, which is a quadratic in sin A. Therefore, sin θ = −2±√−4(4)(−1)2(4). ⇒ sin θ ...
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