Question

evaluate (1+tan² 60)²​

Answer 1

Answer:

[1+(√3)^2]^2=[1+3]^2=[4]^2=16

Answer 2

( 1 + tan² 60° )² = 16

Given :

The expression ( 1 + tan² 60° )²

To find :

The value of the expression

Solution :

Step 1 of 2 :

Write down the given expression

The given expression is

( 1 + tan² 60° )²

Step 2 of 2 :

Find the value of the expression

( 1 + tan² 60° )²

$\sf = {[1 + {( \sqrt{3} )}^{2} ]}^{2}$

$\sf = {(1 + 3 )}^{2}$

$\sf = {4}^{2}$

$\sf = 16$

━━━━━━━━━━━━━━━━

Learn more from Brainly :-

$1.$ value of(1+tan13)(1+tan32)+(1+tan12)(1+tan33)

https://brainly.in/question/23306292

2. Find the value of p if

3cosec2A(1+COSA)(1 - COSA) =p

https://brainly.in/question/23381523