Question

Evaluate
(1+tan²A) (1-sin²A)​

Answer 1

Answer:

Step-by-step explanation:1+tansq.A=secsq.A

And 1-sinsqA=cossqA

Then, secsqA.cossq.A=1

Answer 2

Step-by-step explanation:

(1+tan²A) (1-sin²A)

= (1+tan^2 A) (cos^2 A)

$( \frac{ { \sin }^{2}a }{ { \cos }^{2}a } ) \: \: ( { \cos }^{2} a)$

=> sin^2 A