Math, asked by manjunath66, 9 months ago

Evaluate (1+ tan²thetha)
(1- Sin²thetha)​

Answers

Answered by Anonymous
1

Answer:

Hello✌️✌️✌️

Step-by-step explanation:

(1+ tan²thetha) = sec²thetha

(1- Sin²thetha) = cos² thetha

Answered by ayanrocky94
0

Answer:

1+tanθ+secθ)(1+cotθ−cscθ)

=(1+

cosθ

sinθ

+

cosθ

1

)(1+

sinθ

cosθ

sinθ

1

)

=

cosθ.sinθ

(cosθ+sinθ+1)(sinθ+cosθ−1)

=

cosθsinθ

(cosθ+sinθ)

2

−1

=

cosθsinθ

cos

2

θ+sin

2

θ+2cosθsinθ−1

=

cosθsinθ

1−1+2sinθcosθ

=2

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