Evaluate (1+x)³ by using Binomial theorem.
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Step-by-step explanation:
ANSWER ✍️
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x^3 + 3x^2 +3x + 1
- Binomial formula for (a+b)^3
=> ^3C_0a^3b^0 + ^3C_1a^2b^1 +^3C_2a^1b^2 + ^3C_3a^0b^3
Here, a = x and b = 1.
=> ^3C_0x^3 + ^3C_1x^2xx1^1 +^3C_2x^1xx1^2 + ^3C_3xx1^3
As color(red)(->^3C_0=^3C_3=1) and color(magenta)(->^3C_1=^3C_2 = 3
=> x^3 + 3x^2 +3x + 1
hope this helps you!!
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