evaluate (10.2)^3 using identity
Answers
Answered by
19
10.2can be written as 10+0.2
by using (a+b)^3=a+b3+3ab(a+b)
10+0.2=10³+0.2³+3*10*0.2(10+0.2)
=1000+1.008+6(10.2)
=1000+1.008+61.2
=1062.208
by using (a+b)^3=a+b3+3ab(a+b)
10+0.2=10³+0.2³+3*10*0.2(10+0.2)
=1000+1.008+6(10.2)
=1000+1.008+61.2
=1062.208
Answered by
5
Answer:
(10+.2)^3=(10)^3+(.2)^3+3×10×(.2)[10+0.2]
=1000+0.008+6.0×10.2.
=1000.008+61.2=1061.208
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