Question

Evaluate 10.2^3using suitable identity class 9 ncert maths ​

Answer 1

Answer:

(10+.2)^3=(10)^3+(.2)^3+3×10×(.2)[10+0.2]

=1000+0.008+6.0×10.2.

=1000.008+61.2=1061.208

Step-by-step explanation:

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Answer 2

Answer:

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