Question

Evaluate (10.3) whole cube

Answer 1

use the identity- (a+b)^3=a^3+b^3+3ab(a+b)
thus,
(10+0.3)^3=10^3+0.3^3+3(10)(0.3)(10+0.3)
=1000+0.027+9(10.3)
=1000+0.027+92.7
=1092.727

hope this helps!!

Answer 2

(10.3) ³ = 1,092.727

(10.1) ³ = 1,030.301

To find,

(10.3) ³

(10.1) ³

Solution:

To evaluate (10.3) ³

(10.3) ³ = (10+0.3) ³

(a + b)³ = a³ + b³+ 3ab(a + b)

(10.3) ³ = 10³ + 0.3³ + 3(10) (0.3) (10+0.3)

(10.3) ³ = 1000+0.027+9(10.3)

(10.3) ³ = 1000+0.027+92.7

(10.3) ³ = 1,092.727

To evaluate (10.1) ³

(10.1) ³ = (10+0.1) ³

(a + b)³ = a³ + b³+ 3ab(a + b)

(10.1) ³ = 10³ + 0.1³ + 3(10) (0.1) (10+0.1)

(10.1) ³ = 1000+0.001+3(10.1)

(10.1) ³ = 1000+0.001+30.3

(10.1) ³ = 1,030.301

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