evaluate (1000)^3-(999)^3 using siitable identity
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Answered by
1
Answer:
2997001
Step-by-step explanation:
a³ - b³ = (a-b) (a²+ab+b²)
1000³ - 999³
= (1000-999) (1000²+1000×999+999²)
= (1) (1000000+999000+998001)
= (1) (2997001)
= 2997001
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