Math, asked by khu70, 8 months ago

evaluate (1000)^3-(999)^3 using siitable identity​

Answers

Answered by asahilthakur
1

Answer:

2997001

Step-by-step explanation:

a³ - b³ = (a-b) (a²+ab+b²)

1000³ - 999³

= (1000-999) (1000²+1000×999+999²)

= (1) (1000000+999000+998001)

= (1) (2997001)

= 2997001

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