Math, asked by rameshkumar8766, 5 months ago

Evaluate (1001)3 please evaluate

Answers

Answered by ItzDinu
8

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(1001)³=(1000+1)³

 Suitable identities is :-

(x+y)³=x³+3x²y+3xy²+y³

∴(1000+1)³

= (1000)³+3(1000)²(1)+3(1000)(1)²+(1)³

= 1000000000 + 3000000 + 3000 + 1

= 1003003001.

Answered by Anonymous
17

Hello mate..

.

(1001)³ = (1000 + 1)³

[ (x + y)³ + 3x²y + 3xy² + ]

=> 1000³ + 3(1000)² (1) + 3 (1000) (1)² + 1³

=> 1000000000 + 3000000 + 3000 + 1

=> 1003003001

HOPE THIS HELPS YOU..


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