Question

evaluate 101*99 by using suitable identity​

Answer 1

Step-by-step explanation:

101*99 =>(100+1)*(100-1) =>

${100}^{2} - {1}^{2} = > 10000 - 1 = > 9999$

$(x + y)(x - y) = > {x}^{2} - {y}^{2}$

Hope it helps you.