Evaluate (101) by using
suitable identity.
Answers
Answered by
0
Answer:
question is incomplete.
please make me brainliest.
Thanq.
Answered by
1
Answer:
101= (100 + 1)
By identity = (a + b)^2= a^2 + b^2 + 2ab
(100)^2 + (1)^2 + 2(100)(1)
10000+1+200
10201
Similar questions