Question

Evaluate 101² using suitable identity.​

Answer 1

Answer:

10201

Step-by-step explanation:

101²= (100+1)²{(a+b)²= a²+ b²+2ab}

=(100)²+(1)²+2(100)(1)

=10000+1+200

=10201

Answer 2

Answer:

10201

Step-by-step explanation:

$(101^{2})$=$(100+1)^{2}$                 Identity Used=$(a+b)^{2}=a^{2}+2ab+b^{2}$

$(100)^{2}+$2x100x1+$(1)^{2}$                                            $\left \ {{a=100} \atop {b=1}} \right.$

=10,000+200+1

=10201

Hope this is helpful!