evaluate (102)3 from
class 9th
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Answered by
4
Heya ✋
Let see your answer !!!!
(102)^3
= (100 + 2)^3
= (100)^3 + (2)^3 + 3 × 100 × 2(100 + 2)
= 10,00,000 + 8 + 600(102)
= 1,00,008 + 61,200
= 1,61,208
Thanks :))))
Let see your answer !!!!
(102)^3
= (100 + 2)^3
= (100)^3 + (2)^3 + 3 × 100 × 2(100 + 2)
= 10,00,000 + 8 + 600(102)
= 1,00,008 + 61,200
= 1,61,208
Thanks :))))
Hetarth4:
its cube
Answered by
1
102=100+2
So, (100+2)^3
Now you can apply the following identity:-
(a+b)^3=a^3+b^3+3×a^2×b+3×a×b^2
Taking a =100 and b =2
If you find it helpful please mark it as brainliest....
So, (100+2)^3
Now you can apply the following identity:-
(a+b)^3=a^3+b^3+3×a^2×b+3×a×b^2
Taking a =100 and b =2
If you find it helpful please mark it as brainliest....
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