Question

Evaluate(102) cube using formula (a+b)3=a3+b3+3a2b+3ab2​

Answer 1

${(a + b)}^{3} = {a}^{3} + {b}^{3} + 3ab(a + b) \\ = > {102}^{3} = {(100 + 2)}^{3} \\ = {100}^{3} + {2}^{3} + 3(100)(100 + 2) \\ = 1000000 + 8 + 30600 \\ = 1030608$

Answer 2

Step-by-step explanation:

= (100+2)^3

= (100)^3+ (2)^3+3×(100)^2× 2+ 3×100×(2)^2

= 1061208

I hope this is help you...