Math, asked by Aleenafatima123, 1 year ago

Evaluate 104 whole cube using suitable identity

Answers

Answered by aman190k
172
hey here is your answer
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given \:    \\ = {104}^{3}  \\  =  {(100 + 4)}^{3}   \\  =  {100}^{3} +  {4}^{3} + 3 \times  {100}^{2}   \times 4 + 3 \times 100 \times  {4}^{2}  \\  \:  \:  \:  \:  \:  \:  \:  \:   \:  \:  \:  \:  \:  \:  \: .............\:  {(a + b)}^{3}  =  {a}^{3}  +  {b}^{3} + 3 {a}^{2}b + 3a {b}^{2}  \\  \\  = 1000000 + 64 + 120000 + 4800 \\  = 1124864
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hope it may helpful to you
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Answered by naiksoham95
44
(104})^3
(100+4)^3 {(a+b)^3=a^3+3a^2b+3ab^2+b^3)
a=100. b=4
=(100)^3+3(100)^2(4)+3(100)(4)^2+(4)^3
=1000000+150000+4800+64
=1154864
I hop it's OK!!☺️
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