Evaluate 104 whole cube using suitable identity
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Answered by
172
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Answered by
44
(104})^3
(100+4)^3 {(a+b)^3=a^3+3a^2b+3ab^2+b^3)
a=100. b=4
=(100)^3+3(100)^2(4)+3(100)(4)^2+(4)^3
=1000000+150000+4800+64
=1154864
I hop it's OK!!☺️
(100+4)^3 {(a+b)^3=a^3+3a^2b+3ab^2+b^3)
a=100. b=4
=(100)^3+3(100)^2(4)+3(100)(4)^2+(4)^3
=1000000+150000+4800+64
=1154864
I hop it's OK!!☺️
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