Question

Evaluate 105×106 and(998) cube using suitable identities​

Answer 1

Step-by-step explanation:

Given:105×106 and(998)³

To find: Evaluate using suitable identities.

Solution:

1) 105×106

Ans:

$105 \times 106 = (100 + 5)(100 + 6) \\ \\ (a + x)(a + y) = {a}^{2} + a(x + y) + xy \\ \\ (100 + 5)(100 + 6) = {(100)}^{2} + 100(5 + 6) + 5 \times 6 \\ \\ = 10000 + 1100 + 30 \\ \\\bold{ 105 \times 106 = 11,130}$

2)998³

Ans:

$( {998)}^{3} = (1000 - 2)^{3} \\ \\ {(a - b)}^{3} = {a}^{3} - {b}^{3} - 3ab(a - b) \\ \\ (1000 - 2)^{3} = {(1000)}^{3} - {(2)}^{3} - 3 \times 1000 \times 2(1000 - 2) \\ \\ = 1000000000 - 8 - 6000 \times 998 \\ \\ = 1000000000 - 5988008 \\ \\\bold{ ( {998)}^{3} = 99,40,11,992}$

Hope it helps you.

To learn more on brainly:

1)evaluate using identities 103*97

https://brainly.in/question/3550781

2)evaluate using suitable identity 103^2

https://brainly.in/question/3081228

Answer 2

Answer:

(998)³=99,40,11,992

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