Question

Evaluate 106 × 95 by using a suitable identity ?

Answer 1

is there 105 and 95 or 94 and 106..............
so,
105×95= (100+5) (100-5)
=100^2-5^2. (a^2+b^2=(a+b)(a-b)
10000-25
=99975

Answer 2

Answer:

a]105*95

=[100+5]*[100-5]

thus by using the identity

[a^2-b^2]=[a+b][a-b]

thus,

105*95=[100+5]*[100-5]

           =100^2-5^2

           =10000-25

           =9975