Question

evaluate 11.6 by using a^2+b^2 ,+2ab​

Answer 1

$here \: (a + b) {}^{2 } = {a}^{2 } + {b}^{2} + 2ab$

$= > (2 + 2.8) {}^{2}$

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Answer 2

Answer:

$134.56$

Step-by-step explanation:

$(11.6)^{2} \\(11+0.6)^{2}\\a^{2}+2ab+b^{2}\\(11)^{2}+(2)(11)(0.6)+(0.6)^{2}\\121+13.2+0.36\\121+13.56\\134.56$

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