Question

evaluate:(13/18×-12/39)-(8/9×-3/4)+(-7/-9÷63/-36)​

Answer 1

Given that,

An expression, $(\dfrac{13}{18}\times \dfrac{-12}{39})-(\dfrac{8}{9}\times \dfrac{-3}{4})+(\dfrac{-7}{-9}/\dfrac{63}{-36})$

To find,

The value of the above expression.

Solution,

Taking first term of the above expression, as :

$(\dfrac{13}{18}\times \dfrac{-12}{39})=\dfrac{-2}{9}$

Now taking second term,

$(\dfrac{8}{9}\times \dfrac{-3}{4})=\dfrac{-2}{3}$

And finally taking the last term,

$(\dfrac{-7}{-9}/\dfrac{63}{-36})=\dfrac{\dfrac{-7}{-9}}{\dfrac{63}{-36}}=\dfrac{-4}{9}$

So,

$(\dfrac{13}{18}\times \dfrac{-12}{39})-(\dfrac{8}{9}\times \dfrac{-3}{4})+(\dfrac{-7}{-9}/\dfrac{63}{-36})=\dfrac{-2}{9}-(\dfrac{-2}{3})+\dfrac{-4}{9}\\\\=0$

So, the value of $(\dfrac{13}{18}\times \dfrac{-12}{39})-(\dfrac{8}{9}\times \dfrac{-3}{4})+(\dfrac{-7}{-9}/\dfrac{63}{-36})$ is 0.

Answer 2

Answer:

= 0

Step-by-step explanation:

13by 12×_4738×_47#^×&#:%