Math, asked by mnandhinisaravanan, 9 months ago

Evaluate 15 sec²27-15 cot²63=?

Answers

Answered by MrBhukkad
1

Answer:

15sec²27° 15cot²63°

= 15sec²(90° 63°) 15cot²63°

= 15cosec²63° 15cot²63°

= 15(cosec²63° cot²63°)

= 15 × 1

= 15

HOPE IT HELPS YOU

Answered by samridhrastogi27
0

Answer:

0

Step-by-step explanation:

15sec²27 - 15cos²63

15(sec²27 - cos²63)

15[sec²27 - cos²(90-63)]

15( sec²27 - sec²27)

15×0

0

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