Math, asked by kashafgour, 2 months ago

evaluate
[17^0 + 18^0] [19^0 – 22^0] [23^0 + 2(24)^0]​

Answers

Answered by Anonymous
5

0

Step-by-step explanation:

[17^0 + 18^0] [19^0 – 22^0] [23^0 + 2(24)^0]

[1+1] [1 – 1] [1+ 2(1)]

(2)(0)(3)

0

Answered by Anonymous
3

Answer:

0

Step-by-step explanation:

Any number power 0 is always 1.

= [ 17^0 + 18^0 ] [ 19^0 – 22^0 ] [ 23^0 + 2 ( 24 )^0 ]

= [ 1 + 1 ] [ 1 - 1 ] [ 1 + 2 ( 1 ) ]

= 2 x 0 x 3

= 0​

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