Math, asked by aslamm, 1 month ago

evaluate
18÷{29−3−[100÷(52×10−200)]×10}=

Answers

Answered by anitayadav3613729
2

Answer:

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Answer is in the attachment

Step-by-step explanation:

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Answered by akansha804
0

Answer:

The correct answer to this question is:

18 ÷ {29 − 3 − [100 ÷ (52 × 10 − 200)] × 10} = 0.786

Step-by-step explanation:

Given,

18 ÷ {29 − 3 − [100 ÷ (52 × 10 − 200)] × 10}

= 18 ÷ {29 − 3 − [100 ÷ ((52×10) − 200)] × 10}

= 18 ÷ {29 − 3 − [100 ÷ (520 − 200)] × 10}

= 18 ÷ {29 − 3 − [100 ÷ (320)] × 10}

= 18 ÷ {29 − 3 − [100 ÷ (320)] × 10}

= 18 ÷ {29 − 3 − [0.3125] × 10}

= 18 ÷ {29 − 3 − (0.3125 × 10)}

= 18 ÷ {29 − 3 − (3.125)}

= 18 ÷ {26 − (3.125)}

= 18 ÷ 22.875

= 0.786

Hence, the value of 18 ÷ {29 − 3 − [100 ÷ (52 × 10 − 200)] × 10} = 0.786

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