Math, asked by Kriti0184, 10 months ago

.............................Evaluate...........................​

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Answered by hrn21agmailcom
1

(I) $ ( x^2 + 2 / x + 1 ) dx

= $ [( x^2 - 1 ) + 3 ] / x + 1 ) dx

= $ ( x^2 - 1 )/ ( x+ 1) + 3/ (x + 1) dx

= $ (x + 1) (x - 1) dx / (x+ 1) + 3dx /(x + 1)

= $ (x- 1) dx + 3 dx /(x + 1)

= $ x dx - $ dx + 3 dx /(x + 1)

= x^2 - x + 3 log (x + 1) + C

(ii) log (x + sin x ) + C

Answered by ritvik86
1

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