Question

evaluate [2^-1 + 3^0 + 5^1 + 7^2 + 9^3 ] / (2/3)^-1

Answer 1

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Here is your answer.
$( {2}^{ - 1} + {3}^{0} + {5}^{1} + {7}^{2} + {9}^{3} ) \div ( \frac{2}{3} ) {}^{ - 1} \\ \\ = ( \frac{1}{2} + 1 + 5 + 49 + 729) \times (\frac{3}{2} ) {}^{1} \\ \\ = ( \frac{1}{2} + 784) \times \frac{3}{2} \\ \\ = ( \frac{1 + 1568}{2} ) \times \frac{3}{2} \\ \\ = \frac{1569}{2} \times \frac{3}{2} \\ \\ = \frac{4707}{4} \\ \\ = 1176.75$

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