Math, asked by rishansha, 1 year ago

evaluate:(2-¹+3-¹+5-¹)°​

Answers

Answered by preeti12805
11

Answer:

Step-by-step explanation:

Answer is 1 coz anything raised to the power 0 is 1


rishansha: plz explain step by step
Answered by pulakmath007
0

\displaystyle \sf{ {( {2}^{ - 1} +  {3}^{ - 1}  +  {5}^{ - 1}  )}^{0}   } = 1

Given :

\displaystyle \sf{ {( {2}^{ - 1} +  {3}^{ - 1}  +  {5}^{ - 1}  )}^{0}   }

To find :

The value of the expression

Solution :

Step 1 of 2 :

Write down the given expression

The given expression is

\displaystyle \sf{ {( {2}^{ - 1} +  {3}^{ - 1}  +  {5}^{ - 1}  )}^{0}   }

Step 2 of 2 :

Simplify the given expression

\displaystyle \sf{ {( {2}^{ - 1} +  {3}^{ - 1}  +  {5}^{ - 1}  )}^{0}   }

\displaystyle \sf{ = {\bigg( \frac{1}{2} +  \frac{1}{3} +  \frac{1}{5}   \bigg)}^{0}   }

\displaystyle \sf{ = {\bigg(   \frac{15 + 10 + 6}{30}   \bigg)}^{0}   }

\displaystyle \sf{ = {\bigg(   \frac{31}{30}   \bigg)}^{0}   }

\displaystyle \sf{ = 1 \:  \:  \:   }\bigg[  \: {a}^{0}  = 1 \:  \: where \: a \ne  0\bigg]

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