evaluate: (2-1 X 3-1 ) ÷ 2-3
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5
Answer:
(2 - 1 × 3 - 1) ÷ 2 - 3
= (2 - 3 - 1) ÷ 2 - 3
= -2 ÷ 2 - 3
= -1 - 3
= (-4)
Answered by
0
Answer:
∫−12∣x3−x∣dx
It is clear that
x3−x⩾0on[−1,0]
x3−x⩽0on[0,1]
x3−x⩾0on[1,2]
Hence the interval of the integral can be subdivided as
∫−12∣x3−x∣dx=∫0−1(x3−x)dx+∫01−(x3−x)dx+∫12(x3−x)dx
=∫−10(x3−x)dx+∫01(x−x3)dx+∫12(x3−x)dx
=[4x4−2x2]−10+[2
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